document.write( "Question 487757: It says to find the vertex, but the fraction is throwing me off.\r
\n" ); document.write( "\n" ); document.write( "1/2x^2+6x+7
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Algebra.Com's Answer #333145 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
this is a quadratic equation in standard form.
\n" ); document.write( "the standard form of a quadratic equation is ax^2 + bx + c = 0
\n" ); document.write( "set your equation to 0 and it becomes:
\n" ); document.write( "(1/2)x^2 + 6x + 7 = 0
\n" ); document.write( "this means that:
\n" ); document.write( "a = (1/2)
\n" ); document.write( "b = 6
\n" ); document.write( "c = 7
\n" ); document.write( "the formula for finding the x value of the vertex is:
\n" ); document.write( "x = -b/2a
\n" ); document.write( "substitute for b and a in this formula to get:
\n" ); document.write( "x = -6 / (2 * (1/2)) which becomes:
\n" ); document.write( "x = -6 / 1 which becomes:
\n" ); document.write( "x = -6
\n" ); document.write( "to find the value of y for the vertex, then substitute -6 in the equation to get:
\n" ); document.write( "y = (1/2)x^2 + 6x + 7 becomes:
\n" ); document.write( "y = (1/2)*(-6)^2 + 6*(-6) + 7 which becomes:
\n" ); document.write( "y = (1/2)*36 - 36 + 7 which becomes:
\n" ); document.write( "y = 18 - 36 + 7 which becomes:
\n" ); document.write( "y = -11
\n" ); document.write( "the vertex should be at the point (x,y) = (-6,-11)
\n" ); document.write( "a graph of your equation looks like this:
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\n" ); document.write( "i drew a horizonal line at y = -11 and a vertical line at x = -6 to show your where the vertex would be.
\n" ); document.write( "it would be at the intersection of the vertical and horizontal line.
\n" ); document.write( "the vertical line is not perfectly vertical, but it should be vertical enough for you to get the idea.\r
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