document.write( "Question 487782: Please help!
\n" ); document.write( "Geometry: A cube has sides of lenght [5] find the area of one side of cube, find the volume of the cube, find the lenght if the diagonal of one of the sides, find teh distance from A to B on a cube
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Algebra.Com's Answer #333142 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Detailed explanation:\r\n" );
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document.write( "Let's find the diagonal AC of the bottom square, drawn in green below:\r\n" );
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document.write( "Triangle ADC is a right triangle, with right angle ADC so we use the\r\n" );
document.write( "Pythagorean theorem:\r\n" );
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document.write( "AC² = AD² + DC² \r\n" );
document.write( "AC² = 5² + 5²\r\n" );
document.write( "AC² = 25 + 25\r\n" );
document.write( "AC² = 50\r\n" );
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document.write( " AC = Ö50 = Ö25×2 = Ö25×Ö2 = 5Ö2\r\n" );
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document.write( "That's the first answer.  So we label that green diagonal 5Ö2\r\n" );
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document.write( "Let's draw the cube's diagonal AB in green also\r\n" );
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document.write( "Triangle ABC is a right triangle with right angle ACB. So we use\r\n" );
document.write( "the Pythagorean theorem to find AB\r\n" );
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document.write( "AB² = AC² + BC²\r\n" );
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document.write( "AB² = (5Ö2)² + 5²\r\n" );
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document.write( "AB² = 5²(Ö2)² + 25\r\n" );
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document.write( "AB² = 25(2) + 25\r\n" );
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document.write( "AB² = 50 + 25\r\n" );
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document.write( "AB² = 75\r\n" );
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document.write( " AB = Ö75 = Ö25×3 = Ö25×Ö3 = 5Ö3\r\n" );
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document.write( "Edwin
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