document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50119>Question 50119</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars are leaving Phils house at precisely at 6:20pm. The first car driven by Phil is headed nother. The second car, driven by Roman, is headed south Phil, because he is nat a good citizen is going 20 MPH faster than Roman. If at 7:50 they are exactly 168 miles apart, how fast is each going? \r<BR>\n" );
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document.write( "Please help me. Not sure of the equation\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33308 by </B><A HREF=/tutors/aboutme.mpl?userid=lkwtcnj><B>lkwtcnj(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lkwtcnj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33308\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To get the distance, you multiply speed by time. So if you let Roman's speed be x, then Phil's speed is x + 20. 1.5 hours has passed. Then Roman has gone 1.5x, and Phil has gone 1.5(x+20). Since they're going in opposite directions, the distance between them is just the sum of their individual distances:\r<BR>\n" );
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document.write( "1.5(x + 20) + 1.5x = 168<BR>\n" );
document.write( "1.5x + (1.5 * 20) + 1.5x = 168<BR>\n" );
document.write( "3x + 30 = 168<BR>\n" );
document.write( "3x = 168 - 30<BR>\n" );
document.write( "3x = 138<BR>\n" );
document.write( "x = 138/3 = 46\r<BR>\n" );
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document.write( "Then Roman is going 46 mph, and Phil is going 46 + 20 = 66 mph. Hope that helps! </SPAN>\n" );
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