document.write( "Question 486830: Samuel has an alloy containing 11% gold. Taylor has 1/2 ounces of an alloy containing 70% gold. They combined their alloys to make an alloy with 36 2/7% gold. Gold is worth $388.31 an ounce at the current market value. Samuel estimated the value of the new alloy to be $164.38 an ounce. How many ounces of Samuel's alloy were used? \n" ); document.write( "
Algebra.Com's Answer #333044 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Samuel has an alloy containing 11% gold. \n" ); document.write( " Taylor has 1/2 ounces of an alloy containing 70% gold. \n" ); document.write( " They combined their alloys to make an alloy with 36 2/7% gold. \n" ); document.write( " Gold is worth $388.31 an ounce at the current market value. \n" ); document.write( " Samuel estimated the value of the new alloy to be $164.38 an ounce. \n" ); document.write( " How many ounces of Samuel's alloy were used \n" ); document.write( ": \n" ); document.write( "Change 36 \n" ); document.write( ": \n" ); document.write( "Let x = amt of Sam's alloy used \n" ); document.write( ": \n" ); document.write( ".11x + .70(.5) = .362857(x+.5) \n" ); document.write( ": \n" ); document.write( ".11x + .35 = .362857x + .18143 \n" ); document.write( ": \n" ); document.write( ".35 - .18143 = .362857x - .11x \n" ); document.write( ": \n" ); document.write( ".16857 = .252857x \n" ); document.write( "x = \n" ); document.write( "x = .667 oz of 11% alloy \n" ); document.write( ": \n" ); document.write( "Check this using the values given \n" ); document.write( ".362857(.6667+.5) = .4233 oz of gold \n" ); document.write( "Find the value \n" ); document.write( ".4233 * 388.31 = $164.37, which is within 1 cent \n" ); document.write( " |