document.write( "Question 487298: Write the following using a single logarithm.\r
\n" ); document.write( "\n" ); document.write( "1/3log a - 3log b + 8log c + 6log b \n" ); document.write( "

Algebra.Com's Answer #333026 by mervh1967(6) $\"\"$ $\"About$

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Use the basic properties of logarithms:\r
\n" ); document.write( "\n" ); document.write( "Remember $\"n%2Alog%28x%29=log%28x%5En%29\"$
\n" ); document.write( "so we can write the expression as:
\n" ); document.write( " $\"log%28a%5E%281%2F3%29%29-log%28b%5E3%29%2Blog%28c%5E8%29%2Blog%28b%5E6%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Now, another property of logs states:
\n" ); document.write( " $\"log%28x%29%2Blog%28y%29=log%28x%2Ay%29\"$ and
\n" ); document.write( " $\"log%28x%29-log%28y%29=log%28x%2Fy%29\"$ \r
\n" ); document.write( "\n" ); document.write( "so the equation becomes:
\n" ); document.write( " $\"log%28a%5E%281%2F3%29%2Ac%5E8%2Ab%5E6%2Fb%5E3%29=log%28a%5E%281%2F3%29%2Ac%5E8%2Ab%5E3%29\"$ \r
\n" ); document.write( "\n" ); document.write( "merv \n" ); document.write( "

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