document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=487034>Question 487034</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the solution to the system 2x - 5y = -1 and x - 3y = -3 by the substitution method </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333024 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the solution to the system 2x - 5y = -1 and x - 3y = -3 by the substitution method\r<BR>\n" );
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document.write( "2x - 5y = - 1 -------- eq (i)\r<BR>\n" );
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document.write( "x - 3y = - 3 ------ x = - 3 + 3y ------ eq (ii)\r<BR>\n" );
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document.write( "Substituting (- 3  + 3y) for x in equation 1 results in:\r<BR>\n" );
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document.write( "2(- 3 + 3y) - 5y = - 1\r<BR>\n" );
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document.write( "- 6 + 6y - 5y = - 1  ------- <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28y_=_5%29 ALIGN=MIDDLE  ALT=\"highlight_green%28y_=_5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Substituting 5 for y in eq (ii) results in: x = - 3 + 3(5) -------- <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28x_=_12%29 ALIGN=MIDDLE  ALT=\"highlight_green%28x_=_12%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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