document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=487289>Question 487289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two numbers differ by 57. Their sum is 185. Find the numbers. I don't understand this whole process. Our teacher wants all the steps. HELP! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #333022 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=333022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two number be x and y.\r<BR>\n" );
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document.write( "Then x-y = 57  (1)<BR>\n" );
document.write( "and  x+y = 185 (2)\r<BR>\n" );
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document.write( "From (1) x-y=57, we can re-arrange and get x = 57+y.\r<BR>\n" );
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document.write( "Now since the x and y in both (1) and (2) are the same x and y, we can take our x=57+y and substitute that value for the x in (2).\r<BR>\n" );
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document.write( "So now our (2) goes from x+y=185 to (57+y)+y=185. Now we can solve for y, 57+2y=185,2y=128, y = 64. So now we can plug in this value for y in either (1) or (2) doesn't matter, to find the value of x. From (1) we get x-64=57, so x =57+64 = 121.\r<BR>\n" );
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document.write( "So now let's check, 121-64 = 57 is true, so our first statement is satisfied. I'll leave it to you to check the second statement. If that is also satisfied, then you have your answer! </SPAN>\n" );
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