document.write( "Question 487208: I need help with an investment problem: Tom made an extra $5000 last year from a part-time job. He invested part of the money at 6% and the rest at 8%. He made a total of $380 in interest. How much was invested at 8%? \n" ); document.write( "
Algebra.Com's Answer #332991 by jorel1380(3719) You can put this solution on YOUR website! .06(n)+.08(5000-n)=380 \n" ); document.write( "6n+8(5000-n)=38000 \n" ); document.write( "6n+40000-8n=38000 \n" ); document.write( "2n=2000 \n" ); document.write( "n=1000 \n" ); document.write( "5000-n=4000 \n" ); document.write( "Tom invested $1000 at 6%, and $4000 at 8%. ☺☺☺☺ \n" ); document.write( " |