document.write( "Question 487103: This spinner is spun 36 times. The spinner landed on A 6 times, on B 21 times, and on C 9 times. Compute the empirical probability that the spinner will land on B.
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document.write( "Please help me!!Thanks a lot \n" );
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Algebra.Com's Answer #332958 by Theo(13342)![]() ![]() You can put this solution on YOUR website! spinner is spun 36 times. \n" ); document.write( "it lands on A 6 times \n" ); document.write( "it lands on B 21 times \n" ); document.write( "it lands on C 9 times.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the empirical probability that it will land on A is equal to 6/36. \n" ); document.write( "the empirical probability that it will land on B is equal to 21/36. \n" ); document.write( "the empirical probability that it will land on C is equal to 9/36.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your answer is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the empirical probability that it will land on B is equal to 21/36.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "empirical means \"from experience\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if something happens x% of the time from past experience, then you can say that the probability that it will occur again is x%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's exactly what we did above.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the x was 21 \n" ); document.write( "the total was 36.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x% would be 21/36 * 100 = 58.3% of the time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the total percent should be equal to 100%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(A) = 6/36 = 16.7% \n" ); document.write( "p(B) = 21/36 = 58.3% \n" ); document.write( "p(C) = 9/36 = 25%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add them all up together and you get 16.7 + 58.3 + 25 = 100% \n" ); document.write( " |