document.write( "Question 487103: This spinner is spun 36 times. The spinner landed on A 6 times, on B 21 times, and on C 9 times. Compute the empirical probability that the spinner will land on B.
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Algebra.Com's Answer #332958 by Theo(13342)\"\" \"About 
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spinner is spun 36 times.
\n" ); document.write( "it lands on A 6 times
\n" ); document.write( "it lands on B 21 times
\n" ); document.write( "it lands on C 9 times.\r
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\n" ); document.write( "\n" ); document.write( "the empirical probability that it will land on A is equal to 6/36.
\n" ); document.write( "the empirical probability that it will land on B is equal to 21/36.
\n" ); document.write( "the empirical probability that it will land on C is equal to 9/36.\r
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\n" ); document.write( "\n" ); document.write( "your answer is:\r
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\n" ); document.write( "\n" ); document.write( "the empirical probability that it will land on B is equal to 21/36.\r
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\n" ); document.write( "\n" ); document.write( "empirical means \"from experience\".\r
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\n" ); document.write( "\n" ); document.write( "if something happens x% of the time from past experience, then you can say that the probability that it will occur again is x%.\r
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\n" ); document.write( "\n" ); document.write( "that's exactly what we did above.\r
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\n" ); document.write( "\n" ); document.write( "the x was 21
\n" ); document.write( "the total was 36.\r
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\n" ); document.write( "\n" ); document.write( "x% would be 21/36 * 100 = 58.3% of the time.\r
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\n" ); document.write( "\n" ); document.write( "the total percent should be equal to 100%.\r
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\n" ); document.write( "\n" ); document.write( "you have:\r
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\n" ); document.write( "\n" ); document.write( "p(A) = 6/36 = 16.7%
\n" ); document.write( "p(B) = 21/36 = 58.3%
\n" ); document.write( "p(C) = 9/36 = 25%\r
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\n" ); document.write( "\n" ); document.write( "add them all up together and you get 16.7 + 58.3 + 25 = 100%
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