document.write( "Question 487084: I want to know how to simplify this...ln(e^(5AB))
\n" ); document.write( "thank you!! \n" ); document.write( "
Algebra.Com's Answer #332956 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
ln(e^(5AB) is equal to:
\n" ); document.write( "5AB * ln(e)
\n" ); document.write( "ln(e) is equal to 1
\n" ); document.write( "therefore your expressions simplifies to:
\n" ); document.write( "5AB.\r
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\n" ); document.write( "\n" ); document.write( "if we let A = 2 and B = 3, then 5AB = 5*2*3 = 30
\n" ); document.write( "your equation is then:
\n" ); document.write( "ln(e^(30))
\n" ); document.write( "you can solve it directly using your calculator or you can solve it by simplifying it as we did before.
\n" ); document.write( "use your calculator to find ln(e^30))
\n" ); document.write( "it should be the same answer as 30*ln(e) which is equal to 30.
\n" ); document.write( "i did on mine and the answer i got was 30.\r
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\n" ); document.write( "\n" ); document.write( "they're the same, as they should be.\r
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\n" ); document.write( "\n" ); document.write( "i don't believe you can simplify it any further than that.
\n" ); document.write( "your answer is:
\n" ); document.write( "ln(e^(5AB)) = 5AB * ln(e) = 5AB\r
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\n" ); document.write( "\n" ); document.write( "you are using one of the basic laws of logarithms that states:\r
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\n" ); document.write( "\n" ); document.write( "log(a^x) = x*log(a)\r
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