document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=487068>Question 487068</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the angle that is complementary to theata?\r<BR>\n" );
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document.write( "a) 63°4'15''<BR>\n" );
document.write( "b) 82.73°  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332946 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For a, first I converted the angle to degrees.<BR>\n" );
document.write( "First convert the minutes, 4, to a decimal part. <BR>\n" );
document.write( "We know that 60 minutes = 1 degree, each minute is 1/60 of a degree.<BR>\n" );
document.write( "thus, 4' is 4/60 = 4/60 of a degree, = 0.067 of a degree.<BR>\n" );
document.write( "1 second = 1/3600 of a degree, so 40'' = 40/3600 of a degree = 0.0111.<BR>\n" );
document.write( "Thus, 63 degrees 4' 15'' = 63 + 0.067 + 0.011 = 63.078 degrees.<BR>\n" );
document.write( "The complement is this angle subtracted from 90, or 26.922.<BR>\n" );
document.write( "A good website for this is http://www.sunearthtools.com/dp/tools/conversion.php<BR>\n" );
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document.write( "For b, 90 - 82.73 = 7.27 degrees.<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
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