document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=487023>Question 487023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is 2 times as long as it is wide. If the area is 18 square feet, find its perimeter </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332916 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 2W<BR>\n" );
document.write( "AREA = L*W = 18<BR>\n" );
document.write( "2W(W) = 18<BR>\n" );
document.write( "2W^2 = 18<BR>\n" );
document.write( "W^2 = 18/2<BR>\n" );
document.write( "W^2 = 9<BR>\n" );
document.write( "W = 3 OR W = -3<BR>\n" );
document.write( "THE WIDTH IS 3 FT<BR>\n" );
document.write( "THE LENGTH IS 2(3)= 6 FT<BR>\n" );
document.write( "The perimeter is:<BR>\n" );
document.write( "P = 2( L + W) = 2 (3 + 6) = 2(9) = 18 ft<BR>\n" );
document.write( "john10:) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );