document.write( "Question 487008: IMMEDIATE HELP PLEASE!!!!! SERIOUSLY!!! PLEASE HELP ME NOW BECAUSE TIME IS RUNNING OUT!!!!!\r
\n" ); document.write( "\n" ); document.write( "When fighting a fire, the velocity v of water being pumped into the air is modeled by the FUNCTION V=squareroot 2hg, where h represents the maximum height of the water and g represents the acceleration due to gravity (32 ft/s^2)\r
\n" ); document.write( "\n" ); document.write( " 1A -PLEASE SOLVE FOR H
\n" ); document.write( "1B- The Babylon Fire Department mus purchase a pump that will propel water 80ft into the air. Will a pump that is advertised to project water with velocity of 70ft per second meet the fire departments need? EXPLAIN.
\n" ); document.write( "

Algebra.Com's Answer #332913 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+V+=+sqrt%282g%2Ah%29+\"
\n" ); document.write( "\"+g+=+32+\" ft/sec
\n" ); document.write( "-----------------
\n" ); document.write( "(1a)
\n" ); document.write( "Square both sides
\n" ); document.write( "\"+V%5E2+=+2g%2Ah+\"
\n" ); document.write( "Divide both sides by \"+2g+\"
\n" ); document.write( "\"+h+=+V%5E2+%2F+%282g%29+\"
\n" ); document.write( "\"+h+=+V%5E2+%2F+64+\"
\n" ); document.write( "(1b)
\n" ); document.write( "given:
\n" ); document.write( "\"+h+=+80+\"
\n" ); document.write( "\"+80+=+V%5E2+%2F+64+\"
\n" ); document.write( "Multiply both sides by \"64\"
\n" ); document.write( "\"+V%5E2+=+5120+\"
\n" ); document.write( "\"+V+=+sqrt%285120%29+\"
\n" ); document.write( "\"+V+\" is between \"71\" and \"72\" ft/sec
\n" ); document.write( "That is the velocity of water that is
\n" ); document.write( "needed to reach a height of \"80\" ft
\n" ); document.write( "A pump that projects water with velocity
\n" ); document.write( "of 70 ft/sec will not reach a height of \"+80+\" ft
\n" ); document.write( "---------------------------
\n" ); document.write( "The height that the water will reach is:
\n" ); document.write( "\"+h+=+V%5E2%2F64+\"
\n" ); document.write( "\"+h+=+70%5E2+%2F+64+\"
\n" ); document.write( "\"+h+=+4900+%2F+64+\"
\n" ); document.write( "\"+h+=+76.56+\" ft
\n" ); document.write( "This is \"+3.44+\" ft short
\n" ); document.write( "
\n" );