document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50071>Question 50071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An investment of P dollars made at the simple interest rate r for t years will grow to a total T=P+Prt. For an investment of $10,000 to grow at least $12,000 in two years, what is the minnimum interest rate at which it can be invested?\r<BR>\n" );
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document.write( "PLEASE HELP ME </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33291 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> T=P+Prt [Original formula]<BR>\n" );
document.write( "12,000=10,000+10,000(r)(2) [Plug-in the values]<BR>\n" );
document.write( "12,000-10,000=10,000-10,000 +10,000(r)(2) {Solve for (r)]<BR>\n" );
document.write( "2,000=10,000(r)(2)<BR>\n" );
document.write( "2,000=20,000(r)<BR>\n" );
document.write( "2,000/20,000=20,000(r)/20,000<BR>\n" );
document.write( "0.10=r=10% = the minimum interest rate<BR>\n" );
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document.write( "check by plugging all of the values back into the original equation. </SPAN>\n" );
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