document.write( "Question 487014: Linda is 3 more than 2 times the age of Jane. In five years the sum of their ages will be 28. What is Linda's age at present ? \n" ); document.write( "
Algebra.Com's Answer #332908 by John10(297)![]() ![]() You can put this solution on YOUR website! Let x be Linda's age and y is Jane's age at present. \n" ); document.write( "x = 3 + 2y \n" ); document.write( "In five years, their ages sum is 28 \n" ); document.write( "(x + 5) + (y + 5) = 28 \n" ); document.write( "(3 + 2y + 5) + y + 5 = 28 \n" ); document.write( "3y + 13 = 28 \n" ); document.write( "3y = 28 - 13 \n" ); document.write( "3y = 15 \n" ); document.write( "y = 15/3 \n" ); document.write( "y = 5 \n" ); document.write( "x = 3 + 2y = 3 + 2(5) = 3 + 10 = 13 \n" ); document.write( "Thus Linda is 13 years old. \n" ); document.write( "john10:) \n" ); document.write( " |