document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=486941>Question 486941</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose y varies jointly as x and z and y=36, when x=1.2 and z=2. Find y when x=0.4 and z=3. How would you solve this problem ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332857 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula is y = k(xz) where k is the variance constant<BR>\n" );
document.write( "Now we find k = ?<BR>\n" );
document.write( "k = y/(xz) = 36/(1.2* 2) = 15<BR>\n" );
document.write( "Now use the new k to find y:<BR>\n" );
document.write( "y = 15(0.4*3) = 18<BR>\n" );
document.write( "John10:) </SPAN>\n" );
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