document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=485864>Question 485864</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you find the length of the sides of a triangle with a perimeter of 37. The measure of side #1 is 8 less than side #2. Side #2 is twice the length of side #3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332783 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = side 3.<BR>\n" );
document.write( "side 2 = 2x<BR>\n" );
document.write( "side 1 = 2x - 8<BR>\n" );
document.write( "x + 2x + 2x - 8 = 37<BR>\n" );
document.write( "5x = 45<BR>\n" );
document.write( "x = 9<BR>\n" );
document.write( "side 1 = 10<BR>\n" );
document.write( "side 2 = 18<BR>\n" );
document.write( "side 3 = 9\r<BR>\n" );
document.write( "\n" );
document.write( "10 + 18 + 9 = 37<BR>\n" );
document.write( "Cleomenius. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );