document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=486209>Question 486209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the hypotenuse of a right triangle is 3 less than twice the shorter keg. the longer leg is 3 more than the shorter leg. find the 3 sides of the triangle<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332770 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332770\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = shorter leg<BR>\n" );
document.write( " x^2 + (x +3)^2 = (2x - 3)^2 <BR>\n" );
document.write( "x^2 + x^2 + 6x + 9 = 4x^2 -12x +9 <BR>\n" );
document.write( "0 = 2x^2 -18x  <BR>\n" );
document.write( "0 = 2x(x - 9) <BR>\n" );
document.write( "x = 9; this is the shorter leg.<BR>\n" );
document.write( "12 is the longer leg.<BR>\n" );
document.write( "15 is the hypotenuse.<BR>\n" );
document.write( "9^2 + 12^2 = 15^2<BR>\n" );
document.write( "81 + 144 = 225. <BR>\n" );
document.write( "This does check.<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
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