document.write( "Question 486725: Hi, I need help in solving this logarith problem:-\r
\n" ); document.write( "\n" ); document.write( "Solve the simultaneous equations\r
\n" ); document.write( "\n" ); document.write( "log(x+y)= 2log(x) (this equation doesn't have any base)
\n" ); document.write( "log(y)= log(2)+ log(x-1)\r
\n" ); document.write( "\n" ); document.write( "My attempt:
\n" ); document.write( "I simplified the first line :-\r
\n" ); document.write( "\n" ); document.write( "log(x+y)= 2log(x)
\n" ); document.write( "=log(x,x+y)= log(x,x^2) (I put the (x) as a base)
\n" ); document.write( "=log(x,x+y)= 2 (I simplified log(x,x^2) to number 2)
\n" ); document.write( "= x^2= x+y\r
\n" ); document.write( "\n" ); document.write( "Similarly I simplified the second line to be (y = 2x-2)\r
\n" ); document.write( "\n" ); document.write( "I don't know what to do any further now.
\n" ); document.write( "

Algebra.Com's Answer #332757 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Your work so far is good!
\n" ); document.write( "1) \"x%5E2+=+x%2By\" and...
\n" ); document.write( "2) \"y+=+2x-2\" Substitute this for y in equaton 1) to get...
\n" ); document.write( "1a) \"x%5E2+=+x%2B%282x-2%29\" Simplify and solve for x:
\n" ); document.write( "1b) \"x%5E2-3x%2B2+=+0\" Solve by factoring:
\n" ); document.write( "1c) \"%28x-1%29%28x-2%29+=+0\" so...
\n" ); document.write( "1d) \"highlight%28x+=+1%29\" or \"highlight%28x+=+2%29\" Now plug each of these, in turn, in equation 2 and solve for y.
\n" ); document.write( "2a) \"y+=+2x-2\" Substitute \"x+=+1\":
\n" ); document.write( "2b) \"highlight%28y+=+0%29\" and...
\n" ); document.write( "2c) \"y+=+2x-2\" Substitute \"x+=+2\":
\n" ); document.write( "2d) \"highlight%28y+=+2%29\"
\n" ); document.write( "So there are four possible solutions:
\n" ); document.write( "(1, 0), (1, 2), (2, 0), (2, 2)
\n" ); document.write( "Let's check them all:
\n" ); document.write( "\"log%28x%2By%29+=+2Log%28x%29\" Substitute \"x+=+1\" and \"y+=+0\"
\n" ); document.write( "\"Log%281%29+=+2Log%281%29\"
\n" ); document.write( "\"0+=+0\" This solution is valid!
\n" ); document.write( "Try the other solutions yourself and see what happens!
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