document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=486706>Question 486706</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On page 48 of the College Geometry, 2nd edition by Musser, Trimpe, and Mauer. Question 17 is a 180 degree angle that is split by <1 and <2. <1 is 9 degrees less than half of <2. Find the measures of <1 and <2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332756 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332756\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Define angle 1 = x and angle 2 = y, with x = (y/2) - 9. The sum of x and y is 180, so\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE (\frac{y}{2} - 9) + y = 180\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \frac{3y}{2} - 9 = 180 \Rightarrow \frac{3y}{2} = 189 \Rightarrow y = 126\">\r<BR>\n" );
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document.write( "Hence x = angle 1 = 54. </SPAN>\n" );
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