document.write( "Question 486698: Find E, the voltage of a circuit, if I = (2-3i) amperes and R = (3+5i) ohms. \n" ); document.write( "

Algebra.Com's Answer #332732 by mervh1967(6) $\"\"$ $\"About$

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Use Ohm's Law E=I*R
\n" ); document.write( "
\n" ); document.write( " $\"E=I%2AR=%282-3%2Ai%29%2A%283%2B5%2Ai%29\"$
\n" ); document.write( " $\"E=6%2B10%2Ai-9%2Ai-15%2Ai%5E2\"$ and since $\"i%5E2=-1\"$ this can be simplified to
\n" ); document.write( " $\"E=6%2B1%2Ai%2B15=%2821%2Bi%29+volts\"$ \r
\n" ); document.write( "\n" ); document.write( "One small comment. Here, R=(3+5i) which should strictly be called Z (the 'Impedance' which is complex) where R is the Real part of Z...\r
\n" ); document.write( "\n" ); document.write( "merv \n" ); document.write( "

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