document.write( "Question 486694: Two aircraft leave simultaneously from an airport, one flying due north and the other due east. The northbound aircraft averages a speed of 100 miles per hour fater than the eatbound aircraft. After 3 hours, the aircraft are 1500 miles apart. Find the average speed of each aircraft. \n" ); document.write( "
Algebra.Com's Answer #332718 by mananth(16946)\"\" \"About 
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they are travelling at right angles to each other.
\n" ); document.write( "At any given instant they form a right triangle with their starting point\r
\n" ); document.write( "\n" ); document.write( "speed of DISABLED_event_one= x
\n" ); document.write( " other = x+100\r
\n" ); document.write( "\n" ); document.write( "using Pythagoras theorem
\n" ); document.write( "x^2+(x+100)^2 = 1500^2
\n" ); document.write( "x^2+x^2+200x+10000=2250000\r
\n" ); document.write( "\n" ); document.write( "2x^2+200x-2240000\r
\n" ); document.write( "\n" ); document.write( "Find the roots of the equation by quadratic formula
\n" ); document.write( "
\n" ); document.write( "a= 2 ,b= 200 ,c= -2240000
\n" ); document.write( "
\n" ); document.write( "b^2-4ac= 40000 - 17920000
\n" ); document.write( "b^2-4ac= 17960000
\n" ); document.write( "\"sqrt%28%0917960000%09%29\"= 4237.92
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( -200 + 4237.92 )/ 4
\n" ); document.write( "x1= 1009.48
\n" ); document.write( "x2=( -200 -4237.92 ) / 4
\n" ); document.write( "x2= -1109.48
\n" ); document.write( "Ignore negative value
\n" ); document.write( "1009.48 mph= speed of one plane \r
\n" ); document.write( "\n" ); document.write( "add 100 to this speed to get speed of other
\n" ); document.write( "m.ananth@hotmail.ca
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