document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=486647>Question 486647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm using the quadratic formula to solve: \r<BR>\n" );
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document.write( "3x=1-1/x\r<BR>\n" );
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document.write( "I multiplied the x out and got: 3x^2=x-1<BR>\n" );
document.write( "I put it in standard form and came up with: 3x^2-x+1<BR>\n" );
document.write( "a=3 b=-1 c=1\r<BR>\n" );
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document.write( "when I work out the equation I get -11 under the radical which would mean there is no real solution.\r<BR>\n" );
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document.write( "did I work out the problem correctly? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332649 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes.<BR>\n" );
document.write( "The domain of real f(x) = 3x + 1/x -1 excludes x=0 and and f(x) < 0 for x < 0 and f(x) > 0 for x > 0, so f(x) = 0 is not possible.<BR>\n" );
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