document.write( "Question 486469: I ihave two problems and need the detailed answers asap
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document.write( "1.Jogging: Two athletes jog 10 miles. One of the athletes jogs 2 miles per hour faster and finishes 10 minutes ahead of the other athlete. Find the average speed of each athlete.
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document.write( "2.Strength of a Beam: The strength of a beam varies jointly as its width w and the square of its thickness t. If a beam 8 inches wide and 5 inches thick supports 650 pounds, how much can a similar beam 6 inches wide and 6 inches thick support?
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document.write( "Please if I can get these asap Thank you so much \n" );
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Algebra.Com's Answer #332612 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! 1.Jogging: Two athletes jog 10 miles. One of the athletes jogs 2 miles per hour faster and finishes 10 minutes ahead of the other athlete. \n" ); document.write( " Find the average speed of each athlete. \n" ); document.write( "Let s = jogging speed of the athlete \n" ); document.write( "then \n" ); document.write( "(s+2) = jogging speed of the faster athlete \n" ); document.write( ": \n" ); document.write( "Change 10 min to \n" ); document.write( ": \n" ); document.write( "Write a time equation \n" ); document.write( ": \n" ); document.write( "slower time - faster time = 10 min \n" ); document.write( " \n" ); document.write( "multiply by 6s(s+2), resulting in \n" ); document.write( "6(s+2)*10 - 6s(10) = s(s+2) \n" ); document.write( ": \n" ); document.write( "10(6s+12) - 60s = s^2 + 2s \n" ); document.write( ": \n" ); document.write( "60s + 120 - 60s = s^2 + 2s \n" ); document.write( "Arrange to form a quadratic equation \n" ); document.write( "s^2 + 2s - 120 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(s+12)(s-10) = \n" ); document.write( "positive solution \n" ); document.write( "s = 10 mph is the speed of the slower \n" ); document.write( "then \n" ); document.write( "10+2 = 12 mph is the speed of the faster \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "2.Strength of a Beam: The strength of a beam varies jointly as its width w and the square of its thickness t. \n" ); document.write( "S = w*t^2*k,where k = the variation constant \n" ); document.write( ": \n" ); document.write( "If a beam 8 inches wide and 5 inches thick supports 650 pounds, \n" ); document.write( "Find k \n" ); document.write( "8*5^2*k = 650 \n" ); document.write( "200k = 650 \n" ); document.write( "k = \n" ); document.write( "k = 3.25 \n" ); document.write( ": \n" ); document.write( "how much can a similar beam 6 inches wide and 6 inches thick support? \n" ); document.write( "s = 6 *6^2*3.25 \n" ); document.write( "s = 702 lb can be support by a 6 by 6\" beam \n" ); document.write( " |