document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=483233>Question 483233</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can anyone pls. answer this question,<BR>\n" );
document.write( "it's all about distance/rate problem.\r<BR>\n" );
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document.write( "While waiting for his date, Noel takes a bus ride at 60 kph to a certain point and then walks back leisurely at 10 kph. The bus ride takes 15 minutes less than his walking. How far does he walk and for how long?\r<BR>\n" );
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document.write( ">>Thank You<< </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332607 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n/60+1/4=n/10<BR>\n" );
document.write( "n+15=6n<BR>\n" );
document.write( "5n=15<BR>\n" );
document.write( "n=3 kilometers<BR>\n" );
document.write( "3 miles @ 60 kph=3 minutes<BR>\n" );
document.write( "3 miles @ 10 kph=3/10 hour =18 minutes<BR>\n" );
document.write( "18 minutes - 3 minutes=15 minutes.. </SPAN>\n" );
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