document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=486486>Question 486486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jen has to lose 7 pounds.How many minutes will it take her.It takes 15 minutes to lose 100 calories and 3500 calories to lose 1 pound.How would I put that into an algebra equation? thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332545 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332545\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jen has to lose 7 pounds.How many minutes will it take her.It takes 15 minutes to lose 100 calories and 3500 calories to lose 1 pound.How would I put that into an algebra equation?<BR>\n" );
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document.write( "Let r = the calorie burn rate<BR>\n" );
document.write( "Let c = the number of calories required to lose 7 lbs<BR>\n" );
document.write( "Then the time required will be the number of calories divided by the rate:<BR>\n" );
document.write( "t = c/r<BR>\n" );
document.write( "Putting in the numbers, we get<BR>\n" );
document.write( "c = 3500 cals/lb * 7 lb = 24500 cal<BR>\n" );
document.write( "r = 100 cal/15 min<BR>\n" );
document.write( "So t = 24500 cal/(100 cal/15 min) = 245*15 = 3675 mins. </SPAN>\n" );
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