document.write( "Question 486393: Need help for the following sum:\r
\n" ); document.write( "\n" ); document.write( "A starts walking north from Point X at 7 a.m. with a speed of 5 km/hr. After 1 hr, B starts from the same point cycling towards the east with a speed of 16 km/hr. At what time will they be at a distance of 52 km from each other? \r
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Algebra.Com's Answer #332506 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
A ---- North ---- 5 km/h\r
\n" ); document.write( "\n" ); document.write( "B----- east ------16km/h (After 1 hour)\r
\n" ); document.write( "\n" ); document.write( "let the time be t \r
\n" ); document.write( "\n" ); document.write( "A distance 5t+5\r
\n" ); document.write( "\n" ); document.write( "B distance 16 t\r
\n" ); document.write( "\n" ); document.write( "(5t+5)^2+(16t)^2=52^2 ( I have used x in place of t)\r
\n" ); document.write( "\n" ); document.write( "25t^2+50t+25+256t^2=52^2
\n" ); document.write( "281t^2+50t-2679 =0
\n" ); document.write( "Find the roots of the equation by quadratic formula
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\n" ); document.write( "a= 281 b= 50 c= -2679
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\n" ); document.write( "b^2-4ac= 2500 - 3011196
\n" ); document.write( "b^2-4ac= 3013696 \"sqrt%28%093013696%09%29\"= 1736
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( -50 + 1736 )/ 562
\n" ); document.write( "x1= 3 3
\n" ); document.write( "x2=( -50 -1736 ) / 562
\n" ); document.write( "x2= -3.18 -3 1/6
\n" ); document.write( "Ignore negative value
\n" ); document.write( "x = 3 hours\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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