document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=485306>Question 485306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A. segment DG, segment EH, segment FT intersects O.<BR>\n" );
document.write( "1.Name two linear pair of angles.<BR>\n" );
document.write( "2.Name the two supplement of angle FOH.<BR>\n" );
document.write( "3.Name the two supplement of angle GOI.<BR>\n" );
document.write( "4.Angle GOH ang anle DOE are _____,_____,and _____.<BR>\n" );
document.write( "B. Ray AL bisects angle KAT. Find the value of x.<BR>\n" );
document.write( "1.measure of angle 3=6x, measure of angle KAT=90-x<BR>\n" );
document.write( "2.measure of angle 1=7x+3, measure of angle 2=6x+7<BR>\n" );
document.write( "3.measure of angle 1=5x-12, measure of angle 2=3x+6<BR>\n" );
document.write( "4.measure of angle 1=x, maesure of angle 3=4x<BR>\n" );
document.write( "5.measure of angle 1=2x-8, measure of angle 3=116<BR>\n" );
document.write( "6.measure of angle 2=x+12, measure of angle 3=6x-20<BR>\n" );
document.write( "C. solve the ff. problems:<BR>\n" );
document.write( "1.Find the measure of an angle which is twice as large as its supplement.<BR>\n" );
document.write( "2.An angle is half as a large as its complement,find its angle.<BR>\n" );
document.write( "3.The measure of a supplement of an angle is 12 more than twice the measure of an angle. find the measures of an angle and its supplement.<BR>\n" );
document.write( "4.A supplement of an angle is six times as large as its complement.Find the measures of the angle,its supplement and its complement.<BR>\n" );
document.write( "5.In a certain linear pair, one angle measures twice as much as the other. what is the measure of the angle?<BR>\n" );
document.write( "6.Three times the measure of the complement of a certain angle is equal to 30 more than the measure of a supplement of that angle.Find the measure of each angle.\r<BR>\n" );
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document.write( "Thanks..pls answer my questions right now if it is ok because i need it right now.its my assignment,thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332504 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For part one, it looks like part one needs some form of a diagram,<BR>\n" );
document.write( " I do not know what O is; is it a line?<BR>\n" );
document.write( "Part two needs to have the angles 1,2,3 identified.<BR>\n" );
document.write( "+++++++++++++++++++++++++++++++++++++++++++++++++++<BR>\n" );
document.write( "So for part three.<BR>\n" );
document.write( "1. 3x = 180 <BR>\n" );
document.write( "x = 60 degrees, the supplement is 120 degrees.<BR>\n" );
document.write( "2. 3x = 90 <BR>\n" );
document.write( "x = 30, the complement is 60 degrees.<BR>\n" );
document.write( "3. x + 12 = 2(180 - x) <BR>\n" );
document.write( "x + 12 = 360 - 2x<BR>\n" );
document.write( "3x = 348<BR>\n" );
document.write( "x = 116 degrees, the supplement is 64 degrees.<BR>\n" );
document.write( "To check, 64 * 2 = 128, - 12 degrees is 116.<BR>\n" );
document.write( "4. 180 - x = 6(90 - x)<BR>\n" );
document.write( " 180 - x = 540 -6x<BR>\n" );
document.write( "5x = 360<BR>\n" );
document.write( "x = 72 degrees, the angle<BR>\n" );
document.write( "complement = 18<BR>\n" );
document.write( "supplement = 108<BR>\n" );
document.write( "18 * 6  = 108 degrees.<BR>\n" );
document.write( "5. A linear pair is 180 degrees.<BR>\n" );
document.write( "3x = 180 degees,<BR>\n" );
document.write( "x = 60 degrees.<BR>\n" );
document.write( "2x = 120 degrees.<BR>\n" );
document.write( "6. 3(90-x ) -30 = 180 - x<BR>\n" );
document.write( "270 -3x -  30  = 180 - x<BR>\n" );
document.write( "240 -3x = 180 - x<BR>\n" );
document.write( "60 = 2x<BR>\n" );
document.write( "30 degrees = x.<BR>\n" );
document.write( "complement = 60<BR>\n" );
document.write( "supplement = 150<BR>\n" );
document.write( "3 * 60 = 180, 180 - 30 = 150 degrees for a check.<BR>\n" );
document.write( "If you could clarify the first two parts we will look at them. They do not look too difficult with the proper information.<BR>\n" );
document.write( "Cleomenius.\r<BR>\n" );
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document.write( " \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );