document.write( "Question 50015: twice a number is 8 less than its square. what is the number? \n" ); document.write( "
Algebra.Com's Answer #33249 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let the required number(s) be n.\r
\n" ); document.write( "\n" ); document.write( "From the problem description, you can write:
\n" ); document.write( "\"2n+=+n%5E2-8\" Subtract 2n from both sides.
\n" ); document.write( "\"n%5E2-2n-8+=+0\" Solve by factoring.
\n" ); document.write( "\"%28n%2B2%29%28n-4%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"n%2B2+=+0\" and/or \"n-4+=+0\"
\n" ); document.write( "If \"n%2B2+=+0\" then \"n+=+-2\"
\n" ); document.write( "If \"n-4+=+0\" then \"n+=+4\"\r
\n" ); document.write( "\n" ); document.write( "There are two solutions to this problem:\r
\n" ); document.write( "\n" ); document.write( "n = -2 and
\n" ); document.write( "n = 4\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "n = -2
\n" ); document.write( "\"2%28-2%29+=+%28-2%29%5E2-8\"
\n" ); document.write( "\"-4+=+4-8\"
\n" ); document.write( "\"-4+=+-4\"\r
\n" ); document.write( "\n" ); document.write( "n = 4\r
\n" ); document.write( "\n" ); document.write( "\"2%284%29+=+%284%29%5E2-8\"
\n" ); document.write( "\"8+=+16-8\"
\n" ); document.write( "\"8+=+8\"\r
\n" ); document.write( "\n" ); document.write( "Both solutions work.
\n" ); document.write( "
\n" );