document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=486333>Question 486333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me finish this hyperbola: this is what it gives me. \r<BR>\n" );
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document.write( "The hyperbola with center at (5, -6), with vertices at (0, -6) and (10, -6), with (15, 0) a point on the hyperbola.\r<BR>\n" );
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document.write( "here is the equation setup: <BR>\n" );
document.write( "( )^2/( )-( )^2/( )=1  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332454 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The hyperbola with center at (5, -6), with vertices at (0, -6) and (10, -6), with (15, 0) a point on the hyperbola. Here is the equation setup: ( )^2/( )-( )^2/( )=1<BR>\n" );
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document.write( "The given equation is that of a hyperbola with horizontal transverse axis of the standard form:<BR>\n" );
document.write( "(x-h)^2/a^2-(y-k)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "For given equation:<BR>\n" );
document.write( "Center: (5,-6) (given)<BR>\n" );
document.write( "length of horizontal transverse axis=10-0=10=2a<BR>\n" );
document.write( "a=5<BR>\n" );
document.write( "a^2=25<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Solving for b^2<BR>\n" );
document.write( "Using given point (15,0) on hyperbola<BR>\n" );
document.write( "(15-5)^2/25-(0+6)^2/b^2=1<BR>\n" );
document.write( "100/25-36/b^2=1<BR>\n" );
document.write( "4-36/b^2=1<BR>\n" );
document.write( "36/b^2=3<BR>\n" );
document.write( "b^2=36/3=12<BR>\n" );
document.write( "...<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "(x-5)^2/25-(y+6)^2/12=1 </SPAN>\n" );
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