document.write( "Question 486346: Bronze which costs $9.10/kg is made by
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document.write( "combining copper which costs $8.90/kg with
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document.write( "tin which costs $9.50/kg. Find the number
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document.write( "of kg of copper and tin required to make
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document.write( "15.3 kg of bronze. \n" );
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Algebra.Com's Answer #332429 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Copper x kg-------- $8.9 \n" ); document.write( "Tin y kg--------$9.5 \n" ); document.write( " \n" ); document.write( "1 x + 1 y = 15.3 .............1 \n" ); document.write( "8.9 x + 9.5 y = 139.23 .............2 (9.1*15.3) \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -9.5 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "-9.5 x -9.5 y = -145.35 \n" ); document.write( "8.9 x 9.5 y = 139.23 \n" ); document.write( "Add the two equations \n" ); document.write( "-0.6 x = -6.12 \n" ); document.write( "/ -0.6 \n" ); document.write( "x = 10.20 kg \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1 x + 1 y = 15.3 \n" ); document.write( "10.2 + 1 y = 15.3 \n" ); document.write( " 1 y = 15.3 -10.2 \n" ); document.write( " 1 y = 5.1 \n" ); document.write( " y = 5.10kg \n" ); document.write( " \n" ); document.write( " |