document.write( "Question 485927: Davin and Iris decided to run at a heart-shaped track with a perimeter of 1600 meters. They start at the same point and run in opposite directions. If the ratio of Davin's speed to Iris's speed is 3:2 and they meet again after 8 minutes, how fast is Davin in meters per minute? \n" ); document.write( "
Algebra.Com's Answer #332312 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Davin and Iris decided to run at a heart-shaped track with a perimeter of 1600 meters. \n" ); document.write( " They start at the same point and run in opposite directions. \n" ); document.write( " If the ratio of Davin's speed to Iris's speed is 3:2 and they meet again after 8 minutes, how fast is Davin in meters per minute? \n" ); document.write( ": \n" ); document.write( "let D = Devin's speed in met/min \n" ); document.write( "let I = Iris's speed \n" ); document.write( ": \n" ); document.write( "When they meet they will have run a total of 1600 meters \n" ); document.write( "Write a distance equation, dist = time * speed \n" ); document.write( ": \n" ); document.write( "D's dist + I's dist = 1600 \n" ); document.write( "8D + 8I = 1600 \n" ); document.write( "simplify, divide by 8 \n" ); document.write( "D + I = 200 \n" ); document.write( "I = (200-D); we can use this form for substitution \n" ); document.write( ": \n" ); document.write( "It says,\"the ratio of Davin's speed to Iris's speed is 3:2 \" \n" ); document.write( " \n" ); document.write( "substitute (200-D) for I \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "2D = 3(200-D) \n" ); document.write( "2D = 600 - 3D \n" ); document.write( "2D + 3D = 600 \n" ); document.write( "D = \n" ); document.write( "D = 120 met/min is Devin's speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the dist each runs (I's speed: 200-120 = 80 met/min) \n" ); document.write( "8(120) = 960 \n" ); document.write( "8(80) = 640 \n" ); document.write( "-------------- \n" ); document.write( "totals: 1600 m, confirms our solution\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |