document.write( "Question 485956: what is the equation of the line (1/6,1/3) and (5/6,1)? \n" ); document.write( "
Algebra.Com's Answer #332297 by mervh1967(6)\"\" \"About 
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A straight line has the equation \"y=m%2Ax%2Bc\" where the slope of the line is m and c is where the line crosses the y axis.\r
\n" ); document.write( "\n" ); document.write( "You have 2 solutions to this equation (1/6,1/3) and (5/6,1) so put these values in the straight line equation...
\n" ); document.write( "the first (x,y) coordinate gives you \"1%2F3=m%2A%281%2F6%29%2Bc\"
\n" ); document.write( "the second leads to \"1=m%2A%285%2F6%29%2Bc\"\r
\n" ); document.write( "\n" ); document.write( "This is a simple simultaneous equation to find m and c.\r
\n" ); document.write( "\n" ); document.write( "Subtracting these 2 equations gives \"%281%2F3-1%29=m%2A%281%2F6-5%2F6%29%2B%28c-c%29\"
\n" ); document.write( "so \"-2%2F3=m%2A%28-2%2F3%29\" which gives m=1\r
\n" ); document.write( "\n" ); document.write( "now put m=1 into either the equations to find c, for example
\n" ); document.write( "\"1%2F3=1%2A%281%2F6%29%2Bc\" and then it is easy to show \"c=1%2F6\"\r
\n" ); document.write( "\n" ); document.write( "so the equation for the line is \"y=x%2B1%2F6\"\r
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