document.write( "Question 485939: three years ago john was 24 years older than his son now john is five time as old as his son how old is john now? \n" ); document.write( "
Algebra.Com's Answer #332275 by mananth(16946)![]() ![]() You can put this solution on YOUR website! son x years \n" ); document.write( "john 5x years\r \n" ); document.write( "\n" ); document.write( "3 years ago their ages were \n" ); document.write( "son x-3 \n" ); document.write( "John 5x-3\r \n" ); document.write( "\n" ); document.write( "5x-3 = x-3+24 \n" ); document.write( "5x-3=x+21 \n" ); document.write( "5x= 21+3 +x \n" ); document.write( "5x-x= 24 \n" ); document.write( "4x=24 \n" ); document.write( "x= 24/4 \n" ); document.write( "x= 6 Son's age now. \n" ); document.write( "John's age = 6*5 =30 years\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |