document.write( "Question 485939: three years ago john was 24 years older than his son now john is five time as old as his son how old is john now? \n" ); document.write( "
Algebra.Com's Answer #332275 by mananth(16946)\"\" \"About 
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son x years
\n" ); document.write( "john 5x years\r
\n" ); document.write( "\n" ); document.write( "3 years ago their ages were
\n" ); document.write( "son x-3
\n" ); document.write( "John 5x-3\r
\n" ); document.write( "\n" ); document.write( "5x-3 = x-3+24
\n" ); document.write( "5x-3=x+21
\n" ); document.write( "5x= 21+3 +x
\n" ); document.write( "5x-x= 24
\n" ); document.write( "4x=24
\n" ); document.write( "x= 24/4
\n" ); document.write( "x= 6 Son's age now.
\n" ); document.write( "John's age = 6*5 =30 years\r
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