document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=485931>Question 485931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat travels upstream for 3 hours. The return trip requires 2 hours. If the speed of the current is 2 km per hour, find the speed of the boat in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332258 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332258\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Boat speed	=x	kph									<BR>\n" );
document.write( "current speed 	2	kph									<BR>\n" );
document.write( "											<BR>\n" );
document.write( "time with current	2	hours									<BR>\n" );
document.write( "time against current 	3	hours									<BR>\n" );
document.write( "Distance = same											<BR>\n" );
document.write( "8(x+2	)	=	3	(	x	-2	)<BR>\n" );
document.write( "8	x	16	=	3	x	-6					<BR>\n" );
document.write( "3	x	-8	x	=	16	-6					<BR>\n" );
document.write( "x 	=	22	kph	Boat speed							<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );