document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=485928>Question 485928</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train leaves station M and travels west at 35 km/hr. One hour later, a faster train leaves station M and also travels west on a parallel track at 40 km/hr. How far from station M will the faster train catch the slower one? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332257 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> before second train leaves station M <BR>\n" );
document.write( "first train is already 35 km ahead.\r<BR>\n" );
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document.write( "Because in 1 hour it travels 35 km.\r<BR>\n" );
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document.write( "catchup distance = 35\r<BR>\n" );
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document.write( "catchup speed = 40 -35 = 5 km/h\r<BR>\n" );
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document.write( "t= distance /speed<BR>\n" );
document.write( "t = 35/5<BR>\n" );
document.write( "t = 7 hours<BR>\n" );
document.write( "it takes 7 hours for second train to catch up.<BR>\n" );
document.write( "In 7 hours it travels 7 * 48 = 280 km </SPAN>\n" );
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