document.write( "Question 485048: Please help me solve this equation step by step:
\n" ); document.write( " $\"+sqrt%283%2B2x%29+%2B+sqrt%282-2x=3%29+\"$ \n" ); document.write( "

Algebra.Com's Answer #332249 by lwsshak3(11628) $\"\"$ $\"About$

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sqrt(3+2x) + sqrt(2-2x)=3
\n" ); document.write( "√(3+2x)=3-√(2-2x)
\n" ); document.write( "square both sides
\n" ); document.write( "3+2x=9-6√(2-2x)+2-2x
\n" ); document.write( "isolate radical
\n" ); document.write( "6√(2-2x)=9+2-2x-2x-3
\n" ); document.write( "6√(2-2x)=-4x+8
\n" ); document.write( "square both sides again
\n" ); document.write( "36(2-2x)=16x^2-64x+64
\n" ); document.write( "72-72x=16x^2-64x+64
\n" ); document.write( "combine like terms then set expression=0
\n" ); document.write( "16x^2+8x-8=0
\n" ); document.write( "2x^2+x-1=0
\n" ); document.write( "(x+1)(2x-1)=0
\n" ); document.write( "x+1=0
\n" ); document.write( "x=-1
\n" ); document.write( "or
\n" ); document.write( "2x-1=0
\n" ); document.write( "x=1/2 \n" ); document.write( "

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