document.write( "Question 49985: I am having problems with this, can someone please help me with this question?\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangular sign is 3feet longer than the width. If the sign has a area of 40 square feet for advertising, find its length and its width.
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Algebra.Com's Answer #33221 by alka(15)\"\" \"About 
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let width = x
\n" ); document.write( "length = x+3
\n" ); document.write( "area = length * width
\n" ); document.write( " 40 = X(X+3)
\n" ); document.write( " 40 = x^2+3x
\n" ); document.write( " x^2+3x-40=0
\n" ); document.write( "x^2+8x-5x-40=0
\n" ); document.write( "x(x+8)-5(x+8)=0
\n" ); document.write( "(x+8)(x-5)=0
\n" ); document.write( "x=-8 OR x=5
\n" ); document.write( "width cannot be negative
\n" ); document.write( "width=5feet
\n" ); document.write( "length=8feet
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