document.write( "Question 49985: I am having problems with this, can someone please help me with this question?\r
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document.write( "The length of a rectangular sign is 3feet longer than the width. If the sign has a area of 40 square feet for advertising, find its length and its width. \n" );
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Algebra.Com's Answer #33221 by alka(15)![]() ![]() ![]() You can put this solution on YOUR website! let width = x \n" ); document.write( "length = x+3 \n" ); document.write( "area = length * width \n" ); document.write( " 40 = X(X+3) \n" ); document.write( " 40 = x^2+3x \n" ); document.write( " x^2+3x-40=0 \n" ); document.write( "x^2+8x-5x-40=0 \n" ); document.write( "x(x+8)-5(x+8)=0 \n" ); document.write( "(x+8)(x-5)=0 \n" ); document.write( "x=-8 OR x=5 \n" ); document.write( "width cannot be negative \n" ); document.write( "width=5feet \n" ); document.write( "length=8feet \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |