document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=485690>Question 485690</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help!<BR>\n" );
document.write( "Howard Hughes, professor emeritus of texas wesleyan college, reportedly attended a record 6136 theatrical shows.  write an expression to represent the average number of theater shows attended if he accumulated the record over y years.\r<BR>\n" );
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document.write( "I am new to algebra and this one i am struggling with.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332170 by </B><A HREF=/tutors/aboutme.mpl?userid=deborabr><B>deborabr(181)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=deborabr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=deborabr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> hi i think that is like this<BR>\n" );
document.write( "6136/x<BR>\n" );
document.write( "because we don't know how long he works in the theater. The average is the total number of theater shows divided by the amount years that he works.<BR>\n" );
document.write( "so, if you want the answer in years would this. And if you want the answer in months would multiplied by 12. like this:<BR>\n" );
document.write( "6136/12x<BR>\n" );
document.write( "i hope to help you about something<BR>\n" );
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