document.write( "Question 49979This question is from textbook Beginning Algebra
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\n" ); document.write( "\n" ); document.write( "3x + 6y = 0
\n" ); document.write( "x=2/3
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Algebra.Com's Answer #33212 by stanbon(75887)\"\" \"About 
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3x + 6y = 0
\n" ); document.write( "x=2/3
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\n" ); document.write( "Substituting get:
\n" ); document.write( "3(2/3)+6y=0
\n" ); document.write( "2+6y=0
\n" ); document.write( "6y=-2
\n" ); document.write( "y=-1/3
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \r
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