document.write( "Question 485589: How do you solve 3x=-x^2+8 \n" ); document.write( "

Algebra.Com's Answer #332112 by deborabr(181) $\"\"$ $\"About$

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3x=-x^2+8
\n" ); document.write( "this is an equation of the second degree
\n" ); document.write( "we pass the members of the right to the left changing the signals positive to negative and vice versa.Now we equate to zero.
\n" ); document.write( "x^2+3x-8=0
\n" ); document.write( "where representing:
\n" ); document.write( "1=a --> is the value or number that folows X^2 and when it's 1 doesn't need show
\n" ); document.write( "3=b --> is the value or number that folows x
\n" ); document.write( "-8=c --> is the value or number single, but don't forget the signal
\n" ); document.write( "Now we use the formula: delta =(b)^2-4*a*c
\n" ); document.write( "substituting
\n" ); document.write( "delta=(3)^2-4(1)(-8)
\n" ); document.write( "delta=(3*3)-4(-8)--> ps:-4(-8), - with - equal +
\n" ); document.write( "delta=9+32
\n" ); document.write( "delta=41
\n" ); document.write( "Use the second formula: x=-(b)/2(a)+/-root delta/2(a)
\n" ); document.write( "Applying it:
\n" ); document.write( "x=-3/2+/-root 41/2
\n" ); document.write( "answers:
\n" ); document.write( "1°x=-3/2+root 41/2
\n" ); document.write( "2°x=-3/2-root 41/2 \n" ); document.write( "

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