document.write( "Question 6219: The area of a rectangular piece of concrete is 120 square feet, and its perimeter is 46 feet. What are the dimensions of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #3321 by arunpaul(104) $\"\"$ $\"About$

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Let the length be = L
\n" ); document.write( "breadth be = B
\n" ); document.write( "as per the question
\n" ); document.write( "B*L =120 Sf eq1
\n" ); document.write( "perimeter = 2(L+B) = 46 ft eq2\r
\n" ); document.write( "\n" ); document.write( "again B = 120/L
\n" ); document.write( "put the value of B in eq2 we have
\n" ); document.write( "2L+(2*(120/L))=46
\n" ); document.write( "or 2L+(240/L)=46
\n" ); document.write( "or 2L^2+240 = 46L
\n" ); document.write( "or L^2+120 = 23L
\n" ); document.write( "or L^2+120 -23L=0\r
\n" ); document.write( "\n" ); document.write( "applying the solution of quadratic equation we have
\n" ); document.write( "a=1
\n" ); document.write( "b=120
\n" ); document.write( "c=-23
\n" ); document.write( "then applying the solution for quadratic equation we have
\n" ); document.write( " $\"L+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$ \r
\n" ); document.write( "\n" ); document.write( "so L = 0.19136150644875 or -120.191361506449
\n" ); document.write( "take the positive value of L we have B= 120/0.19136150644875 =627.28\r
\n" ); document.write( "\n" ); document.write( "this seems some thing wrong in question though the solution is here
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