document.write( "Question 49966: The length of a rectangle is 6 in. more than twice its width. If the perimeter of the rectangle is 30 in., find the width of the rectangle \n" ); document.write( "
Algebra.Com's Answer #33207 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! The perimeter of a rectangle is given by: \n" ); document.write( "P = 2L + 2W Substitute: P = 30, L = 2W+6, and W = W \n" ); document.write( "30 = 2(2W+6) + 2W Simplify. \n" ); document.write( "30 = 4W+12+2W \n" ); document.write( "30 = 6W+12 Subtract 12 from both sides. \n" ); document.write( "18 = 6W Divide both sides by 6 \n" ); document.write( "3 = W\r \n" ); document.write( "\n" ); document.write( "The width of the rectangle is 3 inches. \n" ); document.write( " |