document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=485559>Question 485559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> &#8736;ABD and &#8736;BDE are supplementary. Find the measures of both angles. \r<BR>\n" );
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document.write( "m&#8736;ABD = 5x°, m&#8736;BDE = (17x-18)°\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #332068 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=332068\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hint: the supplementary angles has the sum of 180<BR>\n" );
document.write( "so 5x + (17x - 18) = 180<BR>\n" );
document.write( "22x - 18 = 180<BR>\n" );
document.write( "22x = 198<BR>\n" );
document.write( "x = 9\r<BR>\n" );
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document.write( "Then <ABD = 5(9) = 45<BR>\n" );
document.write( "< BDE = 17(9) - 18 = 153 - 18 = 135<BR>\n" );
document.write( "John10:) </SPAN>\n" );
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