document.write( "Question 485368: a man drives regularly from his office to his home when he drives 36 kph he arrives home 3 minutes late than usual. When he drives 45 kph he arrives 3 minutes earlier than usual. Find his usual and the distance from his office to his home? \n" ); document.write( "
Algebra.Com's Answer #332009 by ankor@dixie-net.com(22740)\"\" \"About 
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a man drives regularly from his office to his home when he drives 36 kph he arrives home 3 minutes late than usual.
\n" ); document.write( " When he drives 45 kph he arrives 3 minutes earlier than usual.
\n" ); document.write( " Find his usual driving time, and the distance from his office to his home?
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\n" ); document.write( "Let t = his usual driving time
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\n" ); document.write( "Change 3 min to hrs. \"3%2F60\" = .05 hrs
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\n" ); document.write( "Write a dist equation, Dist = speed * time
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\n" ); document.write( "45(t-.05) = 36(t+.05)
\n" ); document.write( "45t - 2.25 = 36t + 1.8
\n" ); document.write( "45t - 36t = 1.8 + 2.25
\n" ); document.write( "9t = 4.05
\n" ); document.write( "t = \"4.05%2F9\"
\n" ); document.write( "t = .45 hrs which is; .45(60) = 27 minutes, his normal driving time
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\n" ); document.write( "Find the distance when he is 3 min early (24 min)
\n" ); document.write( "45*\"24%2F60\" = 18 km
\n" ); document.write( ":
\n" ); document.write( "Check the distance when he is 3 min late (30 min)
\n" ); document.write( "36*\"30%2F60\" = 18 km
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\n" ); document.write( "Summarize, 27 min normal drive time, 18 km is the distance
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