document.write( "Question 49728This question is from textbook
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document.write( ": Science and Medicine: the equation h=16r^2+112t gives the height of an arrow shot upward from the ground with an initial velocity of 112f/s where t is the time after the arrow leaves the ground find the time it takes for the arrow to reach a height of 180f \n" );
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Algebra.Com's Answer #33199 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! I think that you have omitted a negative sign from the first term ot the equation: The general form for the function describing the height (as a funtion of time, t) of an object propelled upwards is: \n" ); document.write( "In your problem, Vo = 112 ft/sec and Ho = 0 (Ground-level), so your equation should be:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "If \n" ); document.write( "If \n" ); document.write( "\n" ); document.write( "The arrow reaches a height of 180 ft in 2.5 seconds on its way up and it passes the 180 foot-level on its way down in 4.5 seconds.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |