document.write( "Question 49728This question is from textbook
\n" ); document.write( ": Science and Medicine: the equation h=16r^2+112t gives the height of an arrow shot upward from the ground with an initial velocity of 112f/s where t is the time after the arrow leaves the ground find the time it takes for the arrow to reach a height of 180f \n" ); document.write( "
Algebra.Com's Answer #33199 by Earlsdon(6294)\"\" \"About 
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I think that you have omitted a negative sign from the first term ot the equation: The general form for the function describing the height (as a funtion of time, t) of an object propelled upwards is: \"h%28t%29+=+-16t%5E2%2BVot%2BHo\" where: Vo is the initial upwards velocity and Ho is the initial height.
\n" ); document.write( "In your problem, Vo = 112 ft/sec and Ho = 0 (Ground-level), so your equation should be:\r
\n" ); document.write( "\n" ); document.write( "\"h%28t%29+=+-16t%5E2%2B112t\" Set h(t) = 180 ft. and solve for t.
\n" ); document.write( "\"180+=+-16t%5E2%2B112t\" Subtract 180 from both sides of the equation.
\n" ); document.write( "\"-16t%5E2%2B112t-180+=+0\" Simplify by factoring out a -4.
\n" ); document.write( "\"-4%284t%5E2-28t%2B45%29+=+0\"
\n" ); document.write( "\"4t%5E2-28t%2B45+=+0\" Solve by factoring.
\n" ); document.write( "\"%282t-5%29%282t-9%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"2t-5+=+0\" and/or \"2t-9+=+0\"
\n" ); document.write( "If \"2t-5+=+0\" then \"2t+=+5\" and \"t+=+2.5\"
\n" ); document.write( "If \"2t-9+=+0\" then \"2t+=+9\" and \"t+=+4.5\"\r
\n" ); document.write( "\n" ); document.write( "The arrow reaches a height of 180 ft in 2.5 seconds on its way up and it passes the 180 foot-level on its way down in 4.5 seconds.\r
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