document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=485420>Question 485420</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me figure this problem out.<BR>\n" );
document.write( "If one of the angle of a triangle is 130 degree, then what will be  the angle between the bisectors of the other two angles?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331989 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x and y be the bisected angles.<BR>\n" );
document.write( "So in the original triangle, sum of angles is<BR>\n" );
document.write( "130 + 2x + 2y = 180<BR>\n" );
document.write( "2(x+y) = 50<BR>\n" );
document.write( "x+y= 25<BR>\n" );
document.write( "In the smaller triangle consisting of the original side opposite 130 and the 2 bisectors, x + y + Ans = 180<BR>\n" );
document.write( "25 + Ans = 180<BR>\n" );
document.write( "Ans = 155<BR>\n" );
document.write( "Or since 180 - Ans is also an answer (perhaps prefered)<BR>\n" );
document.write( "Answer = 25<BR>\n" );
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