document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=49698>Question 49698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please help me with this problem? Every time I try, I end up with decimal coefficients or fractions, or both.\r<BR>\n" );
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document.write( "-4x=10x^2-24x^3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33194 by </B><A HREF=/tutors/aboutme.mpl?userid=hulamc723><B>hulamc723(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hulamc723><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33194\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -4x=10x^2-24x^3\r<BR>\n" );
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document.write( "First, add 4x to both sides so you get 10x^2-24x^3+4x=0<BR>\n" );
document.write( "Then, put the monomials in descending order (-24x^3+10x^2+4x=0)<BR>\n" );
document.write( "Now, factor out a 2x form the equation 2x(-12x^2+5x+2)=0<BR>\n" );
document.write( "Now we are going to set up a table to solve for the problem<BR>\n" );
document.write( "To do the table, we need to have two sections; The sum of five and the product of -12 and 2 (-24)<BR>\n" );
document.write( "To do this we need to find numbers that, when multiplied together, equal -24 and if, when added together, equal five, we know that they are the two numbers that we are going to need to factor the equation!\r<BR>\n" );
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document.write( "Sum of 5         Product of -24  <BR>\n" );
document.write( "-23(not option)      -24,1    <BR>\n" );
document.write( "23(not option)       24,-1<BR>\n" );
document.write( "-10(not option)      -12,2<BR>\n" );
document.write( "10(not option)       2,-12 <BR>\n" );
document.write( "2(not option)        6,-4<BR>\n" );
document.write( "-2(not option)       -4,6\r<BR>\n" );
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document.write( "Now, since none of the numbers add up to 5, we are going to need to use the quadratic formula<BR>\n" );
document.write( "x=-b +or- the square root of b^2-4(a)(c)/2a<BR>\n" );
document.write( "now a=-12, b=5, and c=2<BR>\n" );
document.write( "so, -5 +or- the square root of 5^2-4(-12)(2)/2(-12)<BR>\n" );
document.write( "-5 +or- the square root of 25+96/-24<BR>\n" );
document.write( "-5 +or- 11/24<BR>\n" );
document.write( "-16/24 and 6/24 or (-2/3 and 1/4) </SPAN>\n" );
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