document.write( "Question 485285: moving company a charges $80 plus $55 an hour to move households across town. moving company b charges $75 an hour for cross town moves. For what lengths of time in moving company b more expensive than moving company a? Write an inequality and solve for time t.
\n" ); document.write( "total charge of company a in t hours
\n" ); document.write( "total charge of company b in t hours
\n" ); document.write( "write the following inequality to determine t
\n" ); document.write( "total charge of company a in t hours>total charge of company b in t hours
\n" ); document.write( "show work \n" ); document.write( "

Algebra.Com's Answer #331921 by Tatiana_Stebko(1539) $\"\"$ $\"About$

You can put this solution on YOUR website!
total charge of company a in t hours is $\"%2880%2B55t%29\"$
\n" ); document.write( "total charge of company b in t hours is $\"75t\"$
\n" ); document.write( "For what lengths of time in moving company b more expensive than moving company a? , So total charge of company a in t hours\n" ); document.write( " $\"80%2B55t%3C75t\"$
\n" ); document.write( " $\"55t-75t%3C-80\"$
\n" ); document.write( " $\"-20t%3C-80\"$ divide by (-20), when we divide inequality by negative number the sign of inequality are changed
\n" ); document.write( " $\"t%3E80%2F20\"$
\n" ); document.write( " $\"t%3E4\"$
\n" ); document.write( "If working time is $\"t%3E4\"$ hours, then moving company b more expensive than moving company a \n" ); document.write( "

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