document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=485279>Question 485279</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of a line perpendicular to the line y = 3x + 9 and containing the point (6, -4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #331914 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=331914\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write the equation of a line perpendicular to the line y = 3x + 9 and containing the point (6, -4)<BR>\n" );
document.write( "***<BR>\n" );
document.write( "Standard form for a straight line: y==mx+b, m=slope, b=y-intercept<BR>\n" );
document.write( "y = 3x + 9<BR>\n" );
document.write( "Slope m of given line=3<BR>\n" );
document.write( "Slope of line perpendicular to given line=negative reciprocal=-1/3<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "y=-x/3+b<BR>\n" );
document.write( "solving for b using given point (6,-4)<BR>\n" );
document.write( "-4=-6+b<BR>\n" );
document.write( "b=2<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "y=-x/3+2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );